Why do the data become zero when using the function fi?


fm = get_fimath(); idx = fi(1,0,1,0,fm); a = (idx+fi(2,0,2,0,fm))*fi(1/3,0,16,17,fm); k = fi(a,0,17,0,fm) function fm = get_fimath() fm = fimath('RoundingMethod', 'Floor',... 'OverflowAction', 'Wrap',... 'ProductMode','FullPrecision',... 'MaxProductWordLength', 128,... 'SumMode','FullPrecision',... 'MaxSumWordLength', 128); end
This code is generated when using the Matlab Coder .  I want to know why is k equal to zero? Is it because of division 1/3?


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It's just like scientific notation
is the short answer to "Why FractionLength can be bigger than WordLength?".
The long answer is the following.
The concept of a binary-point is very useful for initial understanding of fixed-point types. Similarly, the concept of a decimal-point is useful for understanding values beyond integers. But using decimal-points becomes very cumbersome for very big or very small numbers. To make it easy to represent very big or very small values, scientific notation is super valuable.
verySmallNumber = 3e-200;
veryBigNumber = 7e123;
In essence, this notation breaks the value into two parts, a mantissa and an integer exponent for the given base.
Y = mantissa .* 10.^exponent
Fixed-point follows the same concept except that
  • base is 2
  • mantissa must be an integer
  • exponent is fixed, i.e. it is part of the variables type and does not change for the life of the variable
Y = intMantissa .* 2^FixedExponent



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