Hi I have a histogram which I want to find its min and max. So lets say the first max happens around 0.1 the local mean is at around 0.3 and second local max is at around 0.8.
ANSWER
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The usual method is to use findpeaks on the inverted signal, so that what were once valleys (minima) now become peaks.
flippedSignal = max(signal) - signal;
By the way, what does this have to do with image processing?
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The usual method is to use findpeaks on the inverted signal, so that what were once valleys (minima) now become peaks.
flippedSignal = max(signal) - signal;
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