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How MATLAB makes the distinction between P-Cores and E-Cores?

  It is known that modern CPUs have both Performance cores (P-cores) and efficiency cores (E-cores), different types of CPU cores that have different purposes and are designed for different tasks. P-cores typically have higher clock speeds and designed for high-performance tasks, while E-cores operate at lower clock speeds and focus on energy-efficient processing. In MATLAB, maxNumCompThreads returns the current maximum number of computational threads. Currently, the maximum number of computational threads is equal to the number of physical cores on your machine. How MATLAB makes the distinction between P-Cores and E-Cores ? NOTE:- Matlabsolutions.com  provide latest  MatLab Homework Help, MatLab Assignment Help  ,  Finance Assignment Help  for students, engineers and researchers in Multiple Branches like ECE, EEE, CSE, Mechanical, Civil with 100% output.Matlab Code for B.E, B.Tech,M.E,M.Tech, Ph.D. Scholars with 100% privacy guaranteed. Get MATLAB projects...

FindPeaks() of a 1024 x 116 Matrix

 I have a matrix that I read into MatLab that is 116 spectra (columns) each being 1024 elements (rows). Each spectrum has a peak and I'm looking to determine the following information from each spectrum:

- Peak value
- Peak position
- Peak width at a set height, like 10% or 30% of the peak height. What I'd really like is to know the first and last x element of each peak
 
I've completed the Signal Processing Toolbox course and it didn't go over the FindPeaks() function. Please, any help would be greatly appreciate. Even if it's direction to a good source on the function. Thank you!


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findpeaks only works on vector input; just use a loop and pass each column of your array in turn.
 
There's a fair amount of background information and examples of using findpeaks in the documentation; I'm unaware of any other tutorial but the web if full of stuff.
 
I'd suggest "just try it" and see what you get. If the spectra are only one-peaked, it seems it could hardly go wrong.
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